MATH SOLVE

4 months ago

Q:
# An investment is currently worth 2.125×104 dollars . Ten years ago, the investment was worth 1.25×103 dollars. How many times greater is the value of the investment today than the value of the investment ten years ago? A 0.17 B 1.7 C 17 D 170

Accepted Solution

A:

Answer: C. 17Step-by-step explanation:Given : An investment is currently worth [tex]2.125\times10^4[/tex] dollars . Ten years ago, the investment was worth [tex]1.25\times10^3[/tex] dollars.Then, the number of times the value of the investment today is greater than the value of the investment ten years ago is given by :-[tex]\dfrac{\text{Current investment}}{\text{\text{Yen years ago investment}}}\\\\=\dfrac{2.125\times10^4}{1.25\times10^3}\\\\=\dfrac{2.125}{1.25}\times10^{4-3}\ \ [\because a^m\times a^n=a^{m+n}]\\\\=1.7\times10=17[/tex]Hence, the value of the investment today is 17 times greater than the value of the investment ten years ago .